Here's the situation, I've got 2 pickups going into a little amp that has 2 inputs, one of which is a low gain, -15db, input, but the amp has only one gain knob. What I want is both pickups to have approximately the same level. I thought I would build a little box with a volume pot on it to go on the hotter input chain, but then I was thinking, "hey! a pot is just a variable resistor, so I should just be able to put the proper resistor in line and that should cut the gain down the necessary amount..."
So, my question is: What's the equation to figure out the right resistor or at least resistor range to accomplish a -15db volume reduction? I've searched around the interwebs but haven't seemed to come up with the right answer or the right way to word my search in order to get a usable result.
PS - fidelity/sonic accuracy is not really an issue as this is for a totally blown out super effected sound.
Thanks in advance!
Proper Resistor for 15db gain reduction
- DrummerMan
- george martin
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- ubertar
- ears didn't survive the freeze
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I don't think there is a simple equation for this... it's going to vary by impedance. I think your best bet is to do it empirically; put a pot in there temporarily, get it set how you like it, take it out and measure it. Replace with a resistor.
A trimpot isn't much bigger than a resistor... you could save a step that way. Just set it and forget it.
A trimpot isn't much bigger than a resistor... you could save a step that way. Just set it and forget it.
What is the amp?
Could be the exact value you need is on the schematic, on the 15dB input.
Other cheap ways to do this, get a Y-cable, connect both pickups to the same input.
Open the amp up, short out the resistor on the 15dB input causing the 15dB loss.
Could be the exact value you need is on the schematic, on the 15dB input.
Other cheap ways to do this, get a Y-cable, connect both pickups to the same input.
Open the amp up, short out the resistor on the 15dB input causing the 15dB loss.
The previous statement is from a guy who records his own, and other projects for fun. No money is made.
- DrummerMan
- george martin
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Good points! I was thinking that I could be super slick and wire the resistor right into the cable plug to have one less thing to lose.ubertar wrote:I don't think there is a simple equation for this... it's going to vary by impedance. I think your best bet is to do it empirically; put a pot in there temporarily, get it set how you like it, take it out and measure it. Replace with a resistor.
A trimpot isn't much bigger than a resistor... you could save a step that way. Just set it and forget it.
- DrummerMan
- george martin
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