So calculate the current. Then calculate the power. Wikipedia and Google will be happy to give you background on Ohm's Law and the Power Law.So I just picked up a crap-ton of resistors, and it seemed to really have put a hurt on the guy at Fistel's electronic cavern... so I really don't want to return them if I don't need to but here's the thing. They are all 1/4W. All of the other designs I have seen have what look like at least 1/2W resistors and I do not know how to figure the current from the outputs of my interface (especially since I just sold it ).
I seem to remember that a full-scale +4 signal is up around 25V but without knowing the current that number is kinda meaningless. I would hate to wire up 64 of these things (16channel) and find out I have to return them. At least they are 1% so I figured I could get away with 5K all around.
Start with Mr Ohm: V = IR.
So you'd have 24 V (not an unreasonable number, maybe a little high, but that just adds some margin), into a 5K load (assuming either an inverting summing amp, or an infinite number of other channels in parallel...reality will be somewhere above 5 K, but again, round numbers give us margin).
24 = I * 5000
24/5000 = 4.8 mA
Then we use Mr Watt: P = IV
24V * .0048 = .1152 W.
Well below .25 Watts, And in real systems, not all channels are driven to max capacity all the time...the signals are transient in nature, lowering the dissipation even further.