Adding External Attack Control to 2-Knob Keeley Compressor

Recording Techniques, People Skills, Gear, Recording Spaces, Computers, and DIY

Moderators: drumsound, tomb

Post Reply
earth tones
steve albini likes it
Posts: 361
Joined: Sun Sep 26, 2004 8:57 pm
Location: Portland, OR

Adding External Attack Control to 2-Knob Keeley Compressor

Post by earth tones » Mon Feb 18, 2013 7:50 am

The older two-knob Keeley compressor pedals did not have an external attack control, but instead had an internal trim pot for making adjustments. I'd like to wire an external potentiometer to control this parameter. Has anybody modded one of these two-knobs Keeley's before and know what value/type of pot to use?

Is it possible take (resistance) measurements of the internal trimpot to determine the proper value of a replacement potentiometer?

kslight
mixes from purgatory
Posts: 2976
Joined: Tue Oct 13, 2009 7:40 pm

Post by kslight » Mon Feb 18, 2013 8:18 am

Yeah. Sometimes you can just look up the code on the trimmer too. Or just experiment with whatever you have lying around? No reason likely that it needs to be an exact match... A quick google search says 2k?

User avatar
Snarl 12/8
cryogenically thawing
Posts: 3511
Joined: Sat Dec 20, 2008 5:01 pm
Location: Right Cheer
Contact:

Post by Snarl 12/8 » Mon Feb 18, 2013 10:24 am

You can totally measure the resistance to see what's in there. you'd have to take it out of the circuit first (I'm almost positive.) Swept all the way one way it'll be zero, swept the other it should be close to whatever value it is, unless it's effed up. You'll also want to figure out whether it's linear or log taper. And whether you want linear or log taper for one you'd be effing with in real time. I guess if you turn the knob halfway and measure and it's roughly half the full value then it'd be linear? But I've never tried that. Usually pots (even trim pots) say what they are somewhere on them.

http://sound.westhost.com/pots.htm#markings
Carl Keil

Almost forgot: Please steal my drum tracks. and more.

Post Reply

Who is online

Users browsing this forum: No registered users and 44 guests